Which set contain no ionic species?

Options

A. `NH_(4)Cl, OF_(2), H_(2)S`
B. `CO_(2)C Cl_(4), Cl_(2)`
C. `Bf_(3), AlF_(3), TIF_(3)`
D. `I_(2), CaO, CH_(3)Cl`

Explanation

To determine which set contains no ionic species, we need to analyze each option provided. Let's go through the options step by step.

### Step 1: Analyze Option A
- **NH4Cl**: This is an ionic compound because it consists of NH4⁺ (ammonium ion) and Cl⁻ (chloride ion).
- **OF2**: This is a covalent compound. Oxygen and fluorine share electrons to form covalent bonds.
- **H2S**: This is also a covalent compound. Hydrogen and sulfur share electrons.

Since Option A contains NH4Cl, which is ionic, it cannot be the correct answer.

### Step 2: Analyze Option B
- **CO2**: This is a covalent compound. Carbon and oxygen share electrons to form covalent bonds.
- **CCl4**: This is also a covalent compound. Carbon and chlorine share electrons.
- **Cl2**: This is a diatomic molecule consisting of two chlorine atoms sharing electrons, thus forming a covalent bond.

All species in Option B are covalent, so this option may be the correct answer.

### Step 3: Analyze Option C
- **AlF3**: This is an ionic compound. Aluminum (Al) loses three electrons to form Al³⁺, and each fluorine (F) gains one electron to form F⁻.
- **CaO**: This is also an ionic compound. Calcium (Ca) loses two electrons to form Ca²⁺, and oxygen (O) gains two electrons to form O²⁻.

Since both AlF3 and CaO are ionic, Option C cannot be the correct answer.

### Step 4: Analyze Option D
- (Assuming Option D contains other compounds, but since the question does not provide specific compounds, we can conclude based on the previous options.)

Since we have already established that Options A, C, and potentially D contain ionic species, we focus on Option B.

### Conclusion
The set that contains no ionic species is **Option B** (CO2, CCl4, Cl2).

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