The strength of bonds by overlapping of atomic orbitals is in order

Options

A. `2s-2s gt 2s-2p gt 2p-2p`
B. `2s-2p lt 2s-2s lt 2p-2p`
C. `2s-2s lt 2s-2p lt 2p-2p`
D. `2p-2p lt 2s-2s lt 2s-2p`

Explanation

To determine the strength of bonds formed by the overlapping of atomic orbitals, we can analyze the types of overlaps and their corresponding strengths. The order of bond strength can be derived from the directional character of the orbitals involved in the bonding.

### Step-by-Step Solution:

1. **Understanding Bond Types**:
- Bonds can be formed by the overlapping of different types of atomic orbitals: s, p, and hybrid orbitals (like sp).
- Sigma (σ) bonds are formed by the head-on overlap of orbitals.

2. **Analyzing Orbital Overlaps**:
- **s-s Overlap**: This involves two s orbitals. The s orbital is spherical, which means it has less directional character. Therefore, the overlap is less effective.
- **p-p Overlap**: This involves two p orbitals. P orbitals have a more directional character due to their shape, allowing for a stronger head-on overlap compared to s orbitals.
- **s-p Overlap**: This involves one s orbital and one p orbital. The overlap is better than s-s but not as strong as p-p due to the directional nature of p orbitals.

3. **Comparing Strengths**:
- Based on the analysis:
- p-p overlap (pp) is stronger than s-p overlap (sp).
- s-p overlap (sp) is stronger than s-s overlap (ss).
- Therefore, the order of bond strength from strongest to weakest is:
- pp > sp > ss

4. **Conclusion**:
- The correct order of bond strength based on the overlapping of atomic orbitals is:
- pp > sp > ss

### Final Answer:
The strength of bonds by overlapping of atomic orbitals is in the order: **pp > sp > ss**.