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The nitrogen atom in NH(3), NH(2)^(-) an...

The nitrogen atom in `NH_(3), NH_(2)^(-)` and `NH_(4)^(+)` are all surrounded by eight electrons. When these species are arranged in increasing order of `H-N-H` bond angle, correct order is:

A

`NH_(3), NH_(2)^(-), NH_(4)^(+)`

B

`NH_(4)^(+), NH_(2)^(-), NH_(3)`

C

`NH_(3), NH_(4)^(+), NH_(2)^(-)`

D

`NH_(2)^(-), NH_(3), NH_(4)^(+)`

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The correct Answer is:
To determine the increasing order of the `H-N-H` bond angle in the species `NH3`, `NH2^(-)`, and `NH4^(+)`, we need to analyze the molecular geometry and the factors affecting the bond angles in these species. ### Step-by-Step Solution: 1. **Identify the Electron Configuration**: - Nitrogen has 5 valence electrons. In all three species, nitrogen is surrounded by a total of 8 electrons due to bonding and lone pairs. 2. **Analyze NH3 (Ammonia)**: - In `NH3`, nitrogen is bonded to three hydrogen atoms and has one lone pair. - The molecular geometry is trigonal pyramidal due to the presence of the lone pair. - The bond angle is approximately 107 degrees. The lone pair exerts a greater repulsive force than bonding pairs, which reduces the bond angle from the ideal tetrahedral angle of 109.5 degrees. 3. **Analyze NH2^(-) (Amide Ion)**: - In `NH2^(-)`, nitrogen is bonded to two hydrogen atoms and has two lone pairs. - The molecular geometry is bent (or angular). - The bond angle is less than that in `NH3` due to increased lone pair-lone pair repulsion. The bond angle is approximately 104.5 degrees. 4. **Analyze NH4^(+) (Ammonium Ion)**: - In `NH4^(+)`, nitrogen is bonded to four hydrogen atoms and has no lone pairs. - The molecular geometry is tetrahedral. - The bond angle is 109.5 degrees, which is the ideal tetrahedral angle. 5. **Order the Bond Angles**: - Based on the analysis: - `NH2^(-)` has the smallest bond angle (approximately 104.5 degrees). - `NH3` has a bond angle of approximately 107 degrees. - `NH4^(+)` has the largest bond angle (109.5 degrees). - Therefore, the increasing order of `H-N-H` bond angles is: - `NH2^(-) < NH3 < NH4^(+)` ### Final Answer: The correct increasing order of `H-N-H` bond angles is: **NH2^(-) < NH3 < NH4^(+)**

To determine the increasing order of the `H-N-H` bond angle in the species `NH3`, `NH2^(-)`, and `NH4^(+)`, we need to analyze the molecular geometry and the factors affecting the bond angles in these species. ### Step-by-Step Solution: 1. **Identify the Electron Configuration**: - Nitrogen has 5 valence electrons. In all three species, nitrogen is surrounded by a total of 8 electrons due to bonding and lone pairs. 2. **Analyze NH3 (Ammonia)**: ...
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VMC MODULES ENGLISH-CHEMICAL BONDING-I & II-Level - 1 (JEE Main)
  1. Which of the following molecules or ions is not linear?

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  2. In carbon-hydrogen-oxygen compounds :

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  3. The shapes of XeO(2)F(2) molecule is

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  4. Which of the following ions has resonating structures?

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  5. Covalency of carbon in the CO molecule is three because

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  6. Which has maximum number of lone pair of electrons present on central ...

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  7. The nitrogen atom in NH(3), NH(2)^(-) and NH(4)^(+) are all surrounde...

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  8. Which of the following has the highest boiling point?

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  9. The correct order of dipole moments of HF, H(2)S and H(2)O is :

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  10. The correct order of increasing bond length of C-H, C-O, C - C and C =...

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  11. Which of the following compound or ion is planar?

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  12. Explain why PCl(5) is trigonal bipyramidal whereas IF(5) is square pyr...

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  13. In diborane (B(2)H(6)), the bond formed between B and B is called :

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  14. Which of the following pairs have identical value of bond order?

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  15. In Be(2) the bond order is

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  16. The number of anti bonding electrons in N(2) is

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  17. A simplified applified of MO theory to the hypotheritical molecule OF ...

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  18. Which of the following pairs have identical value of bond order?

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  19. Paramagnetism is exhibited by :

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  20. N(2) and O(2) are converted into mono anions, N(2)^(-) and O(2)^(-) ...

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