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Which of the following compound or ion i...

Which of the following compound or ion is planar?

A

`SF_(5)^(-)`

B

`SF_(4)`

C

`SOF_(4)`

D

`SF_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds or ions is planar, we will analyze each option based on their hybridization and molecular geometry. ### Step-by-Step Solution: 1. **Identify the Compounds/Ions**: We are given three compounds/ions to analyze: SF5^-, SF4, and SOF4. 2. **Analyze SF5^-**: - **Valence Electrons Calculation**: - Sulfur (S) has 6 valence electrons. - Each Fluorine (F) has 7 valence electrons, and there are 5 Fluorine atoms. - Total = 6 + (7 × 5) + 1 (due to the negative charge) = 6 + 35 + 1 = 42 electrons. - **Electron Pairs Calculation**: - Divide 42 by 2 to find the number of electron pairs: 42 / 2 = 21 pairs. - **Hybridization**: - The number of bonding pairs (5) + lone pairs (1) = 6 pairs indicates sp^3d^2 hybridization. - **Geometry**: - sp^3d^2 corresponds to an octahedral geometry. - In an octahedral structure, 4 bonds are in the plane, while 2 are above and below the plane. - **Conclusion**: SF5^- is **not planar**. 3. **Analyze SF4**: - **Valence Electrons Calculation**: - Sulfur (S) has 6 valence electrons. - Total for 4 Fluorine atoms = 6 + (7 × 4) = 6 + 28 = 34 electrons. - **Electron Pairs Calculation**: - Divide 34 by 2: 34 / 2 = 17 pairs. - **Hybridization**: - 5 pairs (4 bonding + 1 lone pair) indicate sp^3d hybridization. - **Geometry**: - sp^3d corresponds to a trigonal bipyramidal structure. - In this structure, 3 bonds lie in the plane, while 2 are above and below the plane. - **Conclusion**: SF4 is **not planar**. 4. **Analyze SOF4**: - **Valence Electrons Calculation**: - Sulfur (S) has 6 valence electrons. - Oxygen (O) has 6 valence electrons. - Total for 4 Fluorine atoms = 6 + 6 + (7 × 4) = 6 + 6 + 28 = 40 electrons. - **Electron Pairs Calculation**: - Divide 40 by 2: 40 / 2 = 20 pairs. - **Hybridization**: - 5 pairs (4 bonding + 1 lone pair) indicate sp^3d hybridization. - **Geometry**: - SOF4 has a structure where the 4 Fluorine atoms are in the plane, and the lone pair of electrons can also be considered in the plane. - **Conclusion**: SOF4 is **planar**. ### Final Answer: Among the compounds analyzed, **SOF4 is planar**.

To determine which of the given compounds or ions is planar, we will analyze each option based on their hybridization and molecular geometry. ### Step-by-Step Solution: 1. **Identify the Compounds/Ions**: We are given three compounds/ions to analyze: SF5^-, SF4, and SOF4. 2. **Analyze SF5^-**: ...
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VMC MODULES ENGLISH-CHEMICAL BONDING-I & II-Level - 1 (JEE Main)
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  2. In carbon-hydrogen-oxygen compounds :

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  3. The shapes of XeO(2)F(2) molecule is

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  4. Which of the following ions has resonating structures?

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  5. Covalency of carbon in the CO molecule is three because

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  6. Which has maximum number of lone pair of electrons present on central ...

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  7. The nitrogen atom in NH(3), NH(2)^(-) and NH(4)^(+) are all surrounde...

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  8. Which of the following has the highest boiling point?

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  9. The correct order of dipole moments of HF, H(2)S and H(2)O is :

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  10. The correct order of increasing bond length of C-H, C-O, C - C and C =...

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  11. Which of the following compound or ion is planar?

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  12. Explain why PCl(5) is trigonal bipyramidal whereas IF(5) is square pyr...

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  13. In diborane (B(2)H(6)), the bond formed between B and B is called :

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  14. Which of the following pairs have identical value of bond order?

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  15. In Be(2) the bond order is

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  16. The number of anti bonding electrons in N(2) is

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  17. A simplified applified of MO theory to the hypotheritical molecule OF ...

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  18. Which of the following pairs have identical value of bond order?

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  19. Paramagnetism is exhibited by :

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  20. N(2) and O(2) are converted into mono anions, N(2)^(-) and O(2)^(-) ...

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