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The sequence that correctly describes th...

The sequence that correctly describes the relative bond strengths pertaining to oxygen molecule and its cation or anion is

A

`O_(2)^(2-) gt O_(2)^(-) gt O_(2) gt O_(2)^(+)`

B

`O_(2) gt O_(2)^(+) gt O_(2)^(-) gt O_(2)^(2-)`,

C

`O_(2)^(+) gt O_(2) gt O_(2)^(2-) gt O_(2)^(-)`

D

`O_(2)^(+) gt O_(2) gt O_(2)^(-) gt O_(2)^(2-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the relative bond strengths of the oxygen molecule (O₂) and its cations (O₂⁺) and anions (O₂⁻, O₂²⁻), we will follow these steps: ### Step 1: Understand Bond Order Bond order is defined as the number of covalent bonds between two atoms. It is directly proportional to bond strength; higher bond order means stronger bonds. ### Step 2: Use Molecular Orbital Theory According to molecular orbital theory, the bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} (\text{Number of electrons in bonding orbitals} - \text{Number of electrons in anti-bonding orbitals}) \] ### Step 3: Calculate Bond Order for O₂ The electronic configuration of O₂ (16 electrons) is: - σ1s² σ*1s² σ2s² σ*2s² σ2p_z² π2p_x² π2p_y² - Bonding electrons: 10 (σ and π orbitals) - Anti-bonding electrons: 6 (σ* and π* orbitals) Using the formula: \[ \text{Bond Order}_{O_2} = \frac{1}{2} (10 - 6) = 2 \] ### Step 4: Calculate Bond Order for O₂⁻ For O₂⁻ (17 electrons), one additional electron goes into the anti-bonding π* orbital: - Bonding electrons: 10 - Anti-bonding electrons: 7 Using the formula: \[ \text{Bond Order}_{O_2^-} = \frac{1}{2} (10 - 7) = 1.5 \] ### Step 5: Calculate Bond Order for O₂²⁻ For O₂²⁻ (18 electrons), two additional electrons go into the anti-bonding orbitals: - Bonding electrons: 10 - Anti-bonding electrons: 8 Using the formula: \[ \text{Bond Order}_{O_2^{2-}} = \frac{1}{2} (10 - 8) = 1 \] ### Step 6: Calculate Bond Order for O₂⁺ For O₂⁺ (15 electrons), one electron is removed from the anti-bonding orbital: - Bonding electrons: 10 - Anti-bonding electrons: 5 Using the formula: \[ \text{Bond Order}_{O_2^+} = \frac{1}{2} (10 - 5) = 2.5 \] ### Step 7: Compare Bond Orders Now we can summarize the bond orders: - O₂⁺: 2.5 - O₂: 2 - O₂⁻: 1.5 - O₂²⁻: 1 ### Step 8: Determine Relative Bond Strengths Since bond strength is directly related to bond order, we can conclude the following order of bond strengths: 1. O₂⁺ (strongest) 2. O₂ 3. O₂⁻ 4. O₂²⁻ (weakest) ### Final Answer The sequence that correctly describes the relative bond strengths pertaining to the oxygen molecule and its cation or anion is: **O₂⁺ > O₂ > O₂⁻ > O₂²⁻**

To determine the relative bond strengths of the oxygen molecule (O₂) and its cations (O₂⁺) and anions (O₂⁻, O₂²⁻), we will follow these steps: ### Step 1: Understand Bond Order Bond order is defined as the number of covalent bonds between two atoms. It is directly proportional to bond strength; higher bond order means stronger bonds. ### Step 2: Use Molecular Orbital Theory According to molecular orbital theory, the bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} (\text{Number of electrons in bonding orbitals} - \text{Number of electrons in anti-bonding orbitals}) \] ...
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