Amongest `H_(2)O,H_(2)S,H_(2)Se` and `H_(2)Te` the one with highest boiling point is :

Options

A. (a) `H_(2)O` because of hydrogen bonding
B. (b) `H_(2)Te` because of higher molecular weight
C. (c) `H_(2)S` because of hydrogen bonding
D. (d) `H_(2)Se` because of lower molecular weight

Explanation

To determine which compound among \( H_2O, H_2S, H_2Se, \) and \( H_2Te \) has the highest boiling point, we will analyze the factors affecting boiling points, particularly focusing on hydrogen bonding.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds to consider:
- Water (\( H_2O \))
- Hydrogen sulfide (\( H_2S \))
- Hydrogen selenide (\( H_2Se \))
- Hydrogen telluride (\( H_2Te \))

2. **Check for Hydrogen Bonding**: Hydrogen bonding occurs when hydrogen is bonded to highly electronegative atoms like oxygen, nitrogen, or fluorine.
- In \( H_2O \), hydrogen is bonded to oxygen, which is highly electronegative. Therefore, \( H_2O \) can form strong hydrogen bonds.
- In \( H_2S \), \( H_2Se \), and \( H_2Te \), hydrogen is bonded to sulfur, selenium, and tellurium, respectively. These elements are less electronegative than oxygen and do not form significant hydrogen bonds.

3. **Compare the Strength of Intermolecular Forces**:
- The presence of hydrogen bonds in \( H_2O \) leads to stronger intermolecular forces compared to the van der Waals forces present in \( H_2S, H_2Se, \) and \( H_2Te \).
- As a result, \( H_2O \) will have a much higher boiling point than the other three compounds.

4. **Consider Molecular Weights**: While \( H_2S, H_2Se, \) and \( H_2Te \) have increasing molecular weights, which could suggest higher boiling points due to increased van der Waals forces, the absence of hydrogen bonding in these compounds means that their boiling points will still be lower than that of \( H_2O \).

5. **Conclusion**: Based on the analysis of hydrogen bonding and molecular weights, we conclude that \( H_2O \) has the highest boiling point among the given compounds.

### Final Answer:
The compound with the highest boiling point is \( H_2O \).

---