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In which of the following molecules /ion...

In which of the following molecules /ions , are all the bonds not equal ?

A

`XeF_(4)`

B

`BF_(4)^(-)`

C

`SF_(4)`

D

`SiF_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given molecules or ions have unequal bond lengths, we will analyze each one step by step. ### Step 1: Analyze Xenon Tetrafluoride (XeF4) - **Valence Electrons**: Xenon (Xe) has 8 valence electrons (group 18), and each fluorine (F) contributes 1 electron. Thus, total = 8 + 4 = 12 electrons. - **Structure**: The molecular geometry is square planar due to the presence of two lone pairs on xenon. - **Bond Lengths**: All four Xe-F bonds are equal because of the symmetrical arrangement in a square planar geometry. ### Step 2: Analyze Boron Tetrafluoride (BF4-) - **Valence Electrons**: Boron (B) has 3 valence electrons, and with the addition of one electron due to the negative charge, we have 4 total. Each fluorine contributes 1 electron, so total = 4 + 4 = 8 electrons. - **Structure**: The molecular geometry is tetrahedral. - **Bond Lengths**: All four B-F bonds are equal due to the tetrahedral symmetry. ### Step 3: Analyze Sulfur Tetrafluoride (SF4) - **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each fluorine contributes 1 electron. Thus, total = 6 + 4 = 10 electrons. - **Structure**: The molecular geometry is trigonal bipyramidal with one lone pair, leading to a seesaw shape. - **Bond Lengths**: The axial bonds (SF) are longer than the equatorial bonds due to the different angles (90° for axial and 120° for equatorial). Therefore, the bond lengths are not equal. ### Step 4: Analyze Silicon Tetrafluoride (SiF4) - **Valence Electrons**: Silicon (Si) has 4 valence electrons, and each fluorine contributes 1 electron. Thus, total = 4 + 4 = 8 electrons. - **Structure**: The molecular geometry is tetrahedral. - **Bond Lengths**: All four Si-F bonds are equal due to the tetrahedral symmetry. ### Conclusion Among the analyzed molecules, only **Sulfur Tetrafluoride (SF4)** has unequal bond lengths. ### Final Answer **The molecule with unequal bond lengths is SF4.** ---

To determine which of the given molecules or ions have unequal bond lengths, we will analyze each one step by step. ### Step 1: Analyze Xenon Tetrafluoride (XeF4) - **Valence Electrons**: Xenon (Xe) has 8 valence electrons (group 18), and each fluorine (F) contributes 1 electron. Thus, total = 8 + 4 = 12 electrons. - **Structure**: The molecular geometry is square planar due to the presence of two lone pairs on xenon. - **Bond Lengths**: All four Xe-F bonds are equal because of the symmetrical arrangement in a square planar geometry. ### Step 2: Analyze Boron Tetrafluoride (BF4-) ...
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