Which one of the following pairs of species have the same bond order?

Options

A. `CN^(-) and NO^(+)`
B. `CN^(-) and CN^(+)`
C. `O_(2)^(-) and CN^(-)`
D. `NO^(+) and CN^(+)`

Answer

A

Explanation

For any species to have same bond order we can expect them to have same number of electrons. Calculating the number of electrons in various species.
`O_(2)^(-) (8+8+1=17), CN^(-) (6+7+1=14)`
`NO^(+) (7+8-1=14), CN^(+)(6+7-1=12)`
We find `CN^(-)` and `NO^(+)` both have 14 electrons so they have same bond order. Correct is (A).