The types of hybrid orbitals of nitrogen in `NO_(2)^(+)`, `NO_(3)^(-)` and `NH_(4)^(+)` respectively are excepted to be

Options

A. `sp, sp^(2),sp^(3)`
B. `sp^(2), sp, sp^(3)`
C. `sp, sp^(3), sp^(2)`
D. `sp^(2), sp^(3), sp`

Answer

B

Explanation

The formula to find the hybridization of central atom is `Z=(1)/(2)` [Number of valence electrons on central atom + No. of monovalent atom attached to it + negative charge if any – positive charge if any]
For `NO_(3)^(-), Z=(1)/(2)[5+0+1-0]=3`

For `NO_(2)^(+), Z=(1)/(2)[5+0+0-1]=2" " O=overset(+)N=O to sp`
For ` NH_(4)^(+), Z=(1)/(2)[5+4+0-1]=4`