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The structure of IF(7) is...

The structure of `IF_(7)` is

A

square pyramidal

B

trigonal bipyramidal

C

octahedral

D

pentagonal bipyramidal

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The correct Answer is:
To determine the structure of IF₇ (iodine heptafluoride), we can follow these steps: ### Step 1: Determine the Valence Electrons Iodine (I) is a halogen and has 7 valence electrons. Fluorine (F), also a halogen, has 7 valence electrons as well. **Hint:** Count the valence electrons for both iodine and fluorine to understand how many bonds can be formed. ### Step 2: Identify the Central Atom In IF₇, iodine is the central atom because it is less electronegative than fluorine and can accommodate more bonds. **Hint:** The central atom in a molecule is typically the least electronegative element. ### Step 3: Determine the Number of Bonds Iodine can form a maximum of 7 bonds (one with each fluorine atom). Therefore, in IF₇, iodine will form 7 single bonds with 7 fluorine atoms. **Hint:** Each bond corresponds to one of the valence electrons from iodine being shared with a fluorine atom. ### Step 4: Determine the Molecular Geometry To visualize the structure, we can use VSEPR (Valence Shell Electron Pair Repulsion) theory. With 7 bonded pairs and no lone pairs, the arrangement of the bonds will be in a specific geometry. **Hint:** Use VSEPR theory to predict the shape based on the number of bonding pairs and lone pairs. ### Step 5: Identify the Shape The molecular geometry of IF₇ is described as "pentagonal bipyramidal." This means that five fluorine atoms are arranged in a pentagonal plane, and the other two fluorine atoms are positioned above and below this plane. **Hint:** Recognize that the term "bipyramidal" indicates that there are two pyramids sharing a base (the pentagonal plane). ### Step 6: Determine the Hybridization The hybridization of the central iodine atom in IF₇ can be determined by counting the number of sigma bonds. Since there are 7 sigma bonds, the hybridization is sp³d³. **Hint:** Hybridization can be determined by the number of bonds formed by the central atom. ### Conclusion The structure of IF₇ is pentagonal bipyramidal with sp³d³ hybridization. ### Final Answer The structure of IF₇ is pentagonal bipyramidal. ---

To determine the structure of IF₇ (iodine heptafluoride), we can follow these steps: ### Step 1: Determine the Valence Electrons Iodine (I) is a halogen and has 7 valence electrons. Fluorine (F), also a halogen, has 7 valence electrons as well. **Hint:** Count the valence electrons for both iodine and fluorine to understand how many bonds can be formed. ### Step 2: Identify the Central Atom ...
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