The correct statement among the following is:

Options

A. `(SiH_(3))_(3)N` is planar and less basic than `(CH_(3))_(3)N`
B. `(SiH_(3))_(3)N` is planar and more basic than `(CH_(3))_(3)N`
C. `(SiH_(3))_(3)N` is pyramidal and less basic than `(CH_(3))_(3)N`
D. `(SiH_(3))_(3)N` is pyramidal and more basic than `(CH_(3))_(3)N`

Answer

A

Explanation

Due to formation of `p pi-d pi` back bonding. `N(SiH_(3))` is `Sp^(2)` hybridized. Hence it is planar and less basic than `N(CH_(3))_(3)`.