Two pi and half sigma bonds are present in:

Options

A. `N_(2)`
B. `N_(2)^(+)`
C. `O_(2)`
D. `O_(2)^(+)`

Answer

B

Explanation

`e^(-) ` configuration of `N_(2)^(+)` is ` " " sigma_(1s^(2))sigma_(1s^(2))^(***)sigma_(2s^(2)) sigma_(2s^(2))^(***) pi_(2p_(x)^(2))pi_(2py^(2))sigma_(2pz^(1))`
Hence B.O is `(2+2+1)/(2)=2.5` Out of which we have `2pi` and `0.5sigma` bond.