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The value of enthalpy change (DeltaH) fo...

The value of enthalpy change (`DeltaH`) for the reaction
`C_2H_5OH(l) + 3O_2(g) to 2CO_2(g) +3H_2O(l)`
at `27^@C` is `-1366.5 kJ mol^(-1)`. The value of internal energy change for the above reaction at this temperature will be

A

`-1371.5 kJ`

B

`-1369.0 kJ`

C

`-1364.0 kJ`

D

`1361.5 kJ`

Text Solution

Verified by Experts

The correct Answer is:
C
Relation between `DeltaH` enthalpy change) and `DeltaE` (internal energy change) is `: Delta H = Delta E + Delta_(n_g) RT`
Where, `Delta_(n_g)` = moles of gaseous products -moles of gaseous reactants = 2 - 3 = -1
`implies -1366.5 = DeltaE - 1 xx 8.314 xx 10^(-3) xx 300`
`Delta E = -1364.0 kJ mol^(-1)`.
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