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For an ideal gas, the heat of reaction a...

For an ideal gas, the heat of reaction at constant pressure and constant volume are related as

A

`H + E = pV`

B

`E = H + pDeltaV`

C

`q_(p) = q_(v) + Delta_(g) nRT`

D

None of these

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The correct Answer is:
To derive the relationship between the heat of reaction at constant pressure (ΔH) and constant volume (ΔU) for an ideal gas, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Definitions**: - ΔH (enthalpy change) is the heat absorbed or released at constant pressure. - ΔU (internal energy change) is the heat absorbed or released at constant volume. 2. **Starting with the Relationship**: - The relationship between ΔH and ΔU can be expressed as: \[ \Delta H = \Delta U + P \Delta V \] - Here, \(P\) is the pressure and \(\Delta V\) is the change in volume. 3. **Considering the Volume Change**: - For reactions involving solids and liquids, the volume change (\(P \Delta V\)) is negligible. Thus, we can simplify the equation for those cases. - However, for gaseous reactions, the volume change cannot be neglected. 4. **Expressing ΔU in Terms of Volume**: - The change in internal energy can be expressed as: \[ \Delta U = P(V_2 - V_1) \] - Where \(V_1\) is the volume of gas phase reactants and \(V_2\) is the volume of gas phase products. 5. **Using the Ideal Gas Law**: - For ideal gases, we can use the ideal gas equation \(PV = nRT\). - For 1 mole of gaseous reactants producing \(n_2\) moles of gaseous products: \[ PV_1 = n_1RT \quad \text{and} \quad PV_2 = n_2RT \] 6. **Substituting into the Equation**: - Substitute these into the equation for ΔH: \[ \Delta H = \Delta U + (n_2RT - n_1RT) \] - Simplifying gives: \[ \Delta H = \Delta U + (n_2 - n_1)RT \] 7. **Defining Δn**: - Let \(\Delta n = n_2 - n_1\), which represents the change in the number of moles of gaseous products minus gaseous reactants. - Thus, we can write: \[ \Delta H = \Delta U + \Delta n \cdot RT \] 8. **Final Relationship**: - Therefore, the relationship between the heat of reaction at constant pressure and constant volume for an ideal gas is: \[ \Delta H = \Delta U + \Delta n \cdot RT \] ### Conclusion: The heat of reaction at constant pressure (ΔH) is related to the heat of reaction at constant volume (ΔU) by the equation: \[ \Delta H = \Delta U + \Delta n \cdot RT \]

To derive the relationship between the heat of reaction at constant pressure (ΔH) and constant volume (ΔU) for an ideal gas, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Definitions**: - ΔH (enthalpy change) is the heat absorbed or released at constant pressure. - ΔU (internal energy change) is the heat absorbed or released at constant volume. ...
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