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The standard enthalpy of formation (Delt...

The standard enthalpy of formation `(Delta_(f)H^(@))` at `298K ` for methane `(CH_(4(g)))` is `-74.8kJ mol^(-1)`. The additional information required to determine the average energy for `C-H` bond formation would be `:`

A

The dissociation energy of hydrogen molecule, `H_(2)`

B

The dissociation energy of `H _ (2)` and enthalpy of sublimation of carbon

C

Latent heat of vaporization of methane

D

The first four ionization energies of carbon and electron gain enthalpy of hydrogen

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To determine the average energy for C-H bond formation in methane (CH₄), we need to consider the enthalpy changes involved in the formation of methane from its constituent elements in their standard states. The standard enthalpy of formation (ΔfH°) for methane is given as -74.8 kJ/mol at 298 K. ### Step-by-Step Solution: 1. **Understanding the Formation Reaction**: The standard enthalpy of formation for methane can be represented by the following reaction: \[ C(s) + 2H_2(g) \rightarrow CH_4(g) \] Here, carbon is in its solid state (graphite), and hydrogen is in its gaseous state. 2. **Identifying Required Enthalpy Changes**: To find the average energy of C-H bond formation, we need to consider the enthalpy changes associated with: - The sublimation of carbon from solid to gas. - The dissociation of hydrogen gas into atomic hydrogen. 3. **Enthalpy of Sublimation of Carbon**: The enthalpy of sublimation (ΔH_sub) is the energy required to convert solid carbon to gaseous carbon: \[ C(s) \rightarrow C(g) \] This value is necessary to account for the energy needed to convert solid carbon into gaseous form before it can bond with hydrogen. 4. **Dissociation Energy of Hydrogen**: The dissociation energy of hydrogen (D_H-H) is the energy required to dissociate molecular hydrogen (H₂) into atomic hydrogen: \[ H_2(g) \rightarrow 2H(g) \] Since we need 2 moles of hydrogen to form one mole of methane, we will need the dissociation energy for 2 moles of H₂. 5. **Calculating the Average Energy of C-H Bonds**: The average energy of C-H bond formation can be calculated using the following relationship: \[ \Delta_fH° = \Delta H_{sub} + D_{H-H} - \text{(Energy of C-H bonds)} \] Rearranging gives us: \[ \text{Energy of C-H bonds} = \Delta H_{sub} + D_{H-H} + \Delta_fH° \] By substituting the known values, we can find the average energy of the C-H bonds. ### Conclusion: To determine the average energy for C-H bond formation, we need: - The dissociation energy of H₂ (to account for the formation of atomic hydrogen). - The enthalpy of sublimation of carbon (to account for the conversion of solid carbon to gaseous carbon).

To determine the average energy for C-H bond formation in methane (CH₄), we need to consider the enthalpy changes involved in the formation of methane from its constituent elements in their standard states. The standard enthalpy of formation (ΔfH°) for methane is given as -74.8 kJ/mol at 298 K. ### Step-by-Step Solution: 1. **Understanding the Formation Reaction**: The standard enthalpy of formation for methane can be represented by the following reaction: \[ C(s) + 2H_2(g) \rightarrow CH_4(g) ...
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