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The value of enthalpy change (DeltaH) fo...

The value of enthalpy change (`DeltaH`) for the reaction
`C_2H_5OH(l) + 3O_2(g) to 2CO_2(g) +3H_2O(l)`
at `27^@C` is `-1366.5 kJ mol^(-1)`. The value of internal energy change for the above reaction at this temperature will be

A

`-1371 . 5 K J`

B

`-1369.0 K J `

C

`-1364.0 K J`

D

`-1361 . 5 K J

Text Solution

Verified by Experts

The correct Answer is:
C
Relation between `Delta H` (enthalpy change) and `Delta E` (internal energy change) is
`Delta H = DeltaE + Delta_(g) nRT`
Where, `Deltan_(g)` = (moles of gaseous products) – (moles of gaseous reactants)
For the given reaction,
`Delta n_(g) = 2- 3 = -1`
`implies -1366.5 = Delta E - 1 xx 8.314 xx 10^(-3) xx 300`
`:. " "Delta E = -1364.0 kJ mol^(-1)`.
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