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Given C(("graphite"))+O(2)(g)toCO(2)(g),...

Given `C_(("graphite"))+O_(2)(g)toCO_(2)(g),`
`Delta_(r)H^(0)=-393.5kJ" "mol^(-1)`
`H_(2)(g)=+(1)/(2)O_(2)(g)toH_(2)O(1),`
`Delta_(r)H^(0)=-285.8" kJ "mol^(-1)`
`CO_(2)(g)+2H_(2)O(1)toCH_(4)(g)+2O_(2)(g)`,
`Delta_(r)H^(0)=+890.3kJ" "mol^(-1)`
Based on the above thermochemical equations, the value of `Delta_(r)H^(0)` at at 298 K for the reaction
`C_(("graphite"))+2H_(2)(g)toCH_(4)(g)` will be:

A

`x = x + y`

B

`y = 2z -x`

C

`x = y - z`

D

`x = y + z`

Text Solution

Verified by Experts

The correct Answer is:
D
Reaction (3) = reaction (1) – (2)
`Delta H_(3) = Delta H_(1) - Delta H_(2)`
`z = x - y`
`x = z + y`.
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