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For a closed container containing 100 mo...

For a closed container containing 100 mole of an ideal gas fitted with movable, frictionless, weightless piston operating such that pressure of gas remains constant at 8.21 atm. Which graph represents correct variation of log V vs. log T where V is in litre and T in kelvin?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
`V=(nR)/P.T`
`rArr log V = log T + log (nR)/p`
`rArr y =mx + c`
where m=1 `rArr theta = 45^(@)`
`C = log (nR)/p = log(100 xx 0.0821)/8.21 =0`
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