The work done in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to a volume of 20 litres at `25^@C` is

Options

A. `-2.303 xx 298 xx 0.082` log 2
B. `-298 xx 10^(7) xx 8.31 xx 2.303 log2`
C. `-2.303 xx 298 xx 0.082 log 0.5`
D. `-8.31 xx 10^(7) xx 298 - 2.303 log 0.5`

Answer

B

Explanation

`w=-nRT ln V_(2)/V_(1) = -1 xx 8.314 xx 298 xx 2.303 log 20/10 = -298 xx 8.314 xx 10^(7) xx 2.303 log 2`