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Consider the reaction at 300 K C(6) ...

Consider the reaction at 300 K
`C_(6) H_(6) (l)+(15)/(2)O_(2)(g)rarr6CO_(2)(g)+3H_(2)O(l), DeltaH = - 3271 kJ`
What is `DeltaU` for the combustion of 1.5 mole of benzene at `27^(@)C` ?

A

`-3271` kJ

B

`-9813` kJ

C

`-4906.5` kJ

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D

From given reaction `Deltan_(g) = 12-15 = -3`
so, `DeltaE^(@) = DeltaH^(@) - Deltan_(g)RT = -6542 + 3RT`
for 1.5 mole, `DeltaE^(@) = 1.5/2 (-6542 + 3RT) = -4900.9` kJ
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