P-V plot for two gases (assuming ideal) during adiabatic processes are given in the Fig. Plot A and plot B should correspond respectively to:

Options

A. He and `H_(2)`
B. `H_(2)` and He
C. He and Ne
D. `H_(2)` and `Cl_(2)`

Answer

B

Explanation

For adiabatic reversible process,
`PV^(lambda) = R rArr P_(2) = P_(1)(V_(1)/V_(2))^(y) ("as" V_(2) gt V_(1))`
`therefore` So final pressure will be more for diatomic gas (less y)