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Calculate the entropy change for the fol...

Calculate the entropy change for the following reaction
`H_(2)(g) +CI_(2)(g) rarr 2HCI (g) at 298 K`
Given `S^(Theta)H_(2) = 131 J K^(-1) mol^(-1), S^(Theta)CI_(2) = 233 J K^(-1) mol^(-1)`, and `S^(Theta) HCI = 187 J K^(-1) mol^(-1)`

A

`10 JK^(-1)mol^(-1)`

B

`-20 JK^(-1) mol^(-1)`

C

`167 JK^(-1) mol^(-1)`

D

`-167 JK^(-1) mol^(-1)`

Text Solution

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The correct Answer is:
To calculate the entropy change for the reaction: \[ \text{H}_2(g) + \text{Cl}_2(g) \rightarrow 2 \text{HCl}(g) \] at 298 K, we can follow these steps: ### Step 1: Write the formula for entropy change The entropy change (\(\Delta S\)) for a reaction can be calculated using the formula: \[ \Delta S = S_{\text{products}} - S_{\text{reactants}} \] ### Step 2: Identify the entropies of the reactants and products From the problem, we have the following standard molar entropies: - \( S^{\Theta}_{\text{H}_2} = 131 \, \text{J K}^{-1} \text{mol}^{-1} \) - \( S^{\Theta}_{\text{Cl}_2} = 233 \, \text{J K}^{-1} \text{mol}^{-1} \) - \( S^{\Theta}_{\text{HCl}} = 187 \, \text{J K}^{-1} \text{mol}^{-1} \) ### Step 3: Calculate the total entropy of products Since there are 2 moles of HCl produced, we calculate the total entropy for the products: \[ S_{\text{products}} = 2 \times S^{\Theta}_{\text{HCl}} = 2 \times 187 \, \text{J K}^{-1} \text{mol}^{-1} = 374 \, \text{J K}^{-1} \text{mol}^{-1} \] ### Step 4: Calculate the total entropy of reactants Now, we calculate the total entropy for the reactants: \[ S_{\text{reactants}} = S^{\Theta}_{\text{H}_2} + S^{\Theta}_{\text{Cl}_2} = 131 \, \text{J K}^{-1} \text{mol}^{-1} + 233 \, \text{J K}^{-1} \text{mol}^{-1} = 364 \, \text{J K}^{-1} \text{mol}^{-1} \] ### Step 5: Calculate the entropy change Now, we can substitute the values into the entropy change formula: \[ \Delta S = S_{\text{products}} - S_{\text{reactants}} = 374 \, \text{J K}^{-1} \text{mol}^{-1} - 364 \, \text{J K}^{-1} \text{mol}^{-1} = 10 \, \text{J K}^{-1} \text{mol}^{-1} \] ### Step 6: Conclusion The entropy change for the reaction at 298 K is: \[ \Delta S = 10 \, \text{J K}^{-1} \text{mol}^{-1} \]

To calculate the entropy change for the reaction: \[ \text{H}_2(g) + \text{Cl}_2(g) \rightarrow 2 \text{HCl}(g) \] at 298 K, we can follow these steps: ### Step 1: Write the formula for entropy change The entropy change (\(\Delta S\)) for a reaction can be calculated using the formula: ...
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