During compression of a spring the work ...

During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy `DeltaU` (in kj) is

`-12`

`-8`

Text Solution

Verified by Experts

The correct Answer is:

`DeltaU = q+W`
`DeltaU = (-2)+10 = 8kJ`

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