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A sample of HI(g) is placed in flask at ...

A sample of `HI(g)` is placed in flask at at pressure of `0.2` atm . At equilibrium the partial pressure of `HI(g)` is `0.04 `atm what is `K_(p)` for the given equilibrium ?
`2HI(g) hArr H_(2)(g) + I_(2)(g)`

Text Solution

Verified by Experts

(Decrease in the pressure of HI = 0.2 – 0.04 = 0.16 atm.)
`K_(p) = (P_(H_(2)) xx P_(I_(2)))/P_(HI)^(2) = (0.08atm xx 0.08atm)/(0.04 atm)^(2) = 4.0`
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