Home
Class 12
CHEMISTRY
In the reaction PCl(5)(g) rarr PCl(3)(g)...

In the reaction `PCl_(5)(g) rarr PCl_(3)(g) + Cl_(2)(g)`
`PCl_(5),PCl_(3)"and"Cl_(2)` are at equilibrium at 500 K. The concentration of `PCl_(3) "and" Cl_(2)` is 1.59M. `K_(c) = 1.79`.Calculate the concentration of `PCl_(5)`.

Text Solution

AI Generated Solution

To solve the problem, we will use the equilibrium constant expression for the given reaction: **Step 1: Write the balanced chemical equation.** The reaction is: \[ PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g) \] **Step 2: Write the expression for the equilibrium constant \( K_c \).** The equilibrium constant \( K_c \) is defined as: ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise Level 0 SA II|6 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise Level 0 LA|6 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - G|10 Videos

  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|98 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|52 Videos

Similar Questions

Explore conceptually related problems

For the reaction PCl_(5)(g) rightarrow PCl_(3)(g) + Cl_(2)(g)

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

PCl_(5), PCl_(3) and Cl_(2) are at equilibrium at 500 K and having concentration 1.59 M PCl_(3), 1.59 M Cl_(2) and 1.41 M PCl_(5) . Calculate K_(c) for the reaction, PCl_(5) hArr PCl_(3) + Cl_(2)

For the reaction PCl_5

PCl_(5),PCl_(3)andCl_(2) are at equilibrium at 500 K with concentration 2.1 M PCl_(3) , 2.1 M Cl_(2) and 1.9 M PCl_(5) . The equilibrium constant for the given reaction is PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))

PCl_(5) overset(Delta)to PCl_(3)+Cl_(2)

PCl_(5) overset(Delta)to PCl_(3)+Cl_(2)

The system PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) attains equilibrium. If the equilibrium concentration of PCl_(3)(g) is doubled, the concentration of Cl_(2)(g) would become

For the gas-phase decomposition, PCl_(5)(g)LeftrightarrowPCl_(3)(g)+Cl_(2)(g)