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On a given condition, the equilibrium co...

On a given condition, the equilibrium concentration of `HI , H_(2)` and `I_(2)` are `0.80` , `0.10` and `0.10` mole/litre. The equilibrium constant for the reaction `H_(2) + I_(2) hArr 2HI` will be

A

8

B

16

C

32

D

64

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(c) = [HI]^(2)/([H_(2)][I_(2)]) = (0.80)^(2)/((0.10)(0.10))`
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