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For the reaction N(2)(g) + 3H(2)(g) rarr...

For the reaction `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) , DeltaH = -93.6 KJ mol^(-1)` the formation of `NH_(3)` is expected to increase at :

A

High pressure and low temperature

B

Low pressure and low temperature

C

High pressure and high temperature

D

Low pressure and high temperature

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To determine the conditions under which the formation of ammonia (NH₃) is expected to increase for the reaction: \[ N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g) \] with a given enthalpy change (\( \Delta H = -93.6 \, \text{kJ mol}^{-1} \)), we can follow these steps: ### Step 1: Identify the Nature of the Reaction The negative value of \( \Delta H \) indicates that the reaction is exothermic. This means that heat is released when ammonia is formed. **Hint:** Remember that exothermic reactions release heat, which influences how temperature changes affect the reaction. ### Step 2: Apply Le Chatelier's Principle According to Le Chatelier's Principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the system will adjust to counteract that change and restore equilibrium. **Hint:** Le Chatelier's Principle helps us predict how changes in conditions will affect the position of equilibrium. ### Step 3: Analyze the Effect of Temperature For exothermic reactions, lowering the temperature favors the formation of products. Thus, to maximize the formation of ammonia, a low temperature is favorable. **Hint:** In exothermic reactions, lower temperatures shift the equilibrium towards the products. ### Step 4: Analyze the Effect of Pressure Next, we consider the effect of pressure. The reaction involves: - 1 mole of nitrogen (N₂) and 3 moles of hydrogen (H₂) on the reactant side, totaling 4 moles. - 2 moles of ammonia (NH₃) on the product side. Increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. In this case, that is the product side (2 moles of NH₃). **Hint:** Increasing pressure favors the side of the reaction with fewer gas moles. ### Step 5: Combine the Findings From the analysis: - Low temperature is favorable for the formation of ammonia. - High pressure is also favorable for the formation of ammonia. Thus, the conditions that would increase the formation of ammonia are high pressure and low temperature. **Final Answer:** The formation of NH₃ is expected to increase at high pressure and low temperature.

To determine the conditions under which the formation of ammonia (NH₃) is expected to increase for the reaction: \[ N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g) \] with a given enthalpy change (\( \Delta H = -93.6 \, \text{kJ mol}^{-1} \)), we can follow these steps: ### Step 1: Identify the Nature of the Reaction The negative value of \( \Delta H \) indicates that the reaction is exothermic. This means that heat is released when ammonia is formed. ...
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