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If a 0.1 M solution of HCN is 0.01% inon...

If a 0.1 M solution of HCN is 0.01% inonized, the ionization constant for HCN is

A

`10^(-3)`

B

`10^(-7)`

C

`10^(-7)`

D

`10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
D
`HCN to H^(+) + CN^(-)`
C - -
`c(1-alpha) calpha calpha`
`K_(a)=(alpha^(2)C)/(1-alpha) approx. alpha^(2)C=10^(-9)`
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