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The following equilibrium exists in aque...

The following equilibrium exists in aqueous solution : `CH_(3)COOH to H^(+) + CH_(3)COO^(-)`If dilute HCl is added :

A

The equilibrium constant will increase

B

The equilibrium constant will decrease

C

Acetate ion concentration will increase

D

Acetate ion concentration will decrease

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The correct Answer is:
To solve the problem, we will analyze the given equilibrium and the effect of adding dilute HCl on it. ### Step-by-Step Solution: 1. **Identify the Equilibrium Reaction:** The equilibrium reaction is: \[ \text{CH}_3\text{COOH} \rightleftharpoons \text{H}^+ + \text{CH}_3\text{COO}^- \] Here, CH₃COOH is acetic acid, which is a weak acid that partially dissociates in water to produce hydrogen ions (H⁺) and acetate ions (CH₃COO⁻). 2. **Effect of Adding Dilute HCl:** When dilute HCl is added to the solution, it dissociates completely to give more H⁺ ions: \[ \text{HCl} \rightarrow \text{H}^+ + \text{Cl}^- \] This increases the concentration of H⁺ ions in the solution. 3. **Applying Le Chatelier's Principle:** According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the system will adjust to counteract the change and restore a new equilibrium. - In this case, the increase in H⁺ concentration will shift the equilibrium to the left (backward direction) to reduce the concentration of H⁺ ions. 4. **Resulting Changes in Concentration:** - As the equilibrium shifts to the left, the concentration of acetate ions (CH₃COO⁻) will decrease because more acetate ions will combine with H⁺ ions to form acetic acid (CH₃COOH). 5. **Conclusion:** Therefore, the correct conclusion is that the concentration of acetate ions (CH₃COO⁻) will decrease upon the addition of dilute HCl. ### Answer: The concentration of acetate ions (CH₃COO⁻) will decrease. ---

To solve the problem, we will analyze the given equilibrium and the effect of adding dilute HCl on it. ### Step-by-Step Solution: 1. **Identify the Equilibrium Reaction:** The equilibrium reaction is: \[ \text{CH}_3\text{COOH} \rightleftharpoons \text{H}^+ + \text{CH}_3\text{COO}^- ...
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