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Which of the following solutions will ha...

Which of the following solutions will have pH = 9 at 298 K?

A

`1xx10^(-9)M` HCl solution

B

`1xx10^(-5)M` NaOH solution

C

`1xx10^(-9)M` KOH solution

D

Both (A) and (B)

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The correct Answer is:
To determine which of the following solutions will have a pH of 9 at 298 K, we need to analyze each option based on the relationship between pH, pOH, and the concentration of hydrogen ions (H⁺) and hydroxide ions (OH⁻) in the solution. ### Step-by-Step Solution: 1. **Understanding pH and pOH**: - pH is defined as \( \text{pH} = -\log[H^+] \) - pOH is defined as \( \text{pOH} = -\log[OH^-] \) - At 298 K, the relationship between pH and pOH is given by \( \text{pH} + \text{pOH} = 14 \). 2. **Option 1: \( 1 \times 10^{-9} \) M HCl Solution**: - HCl is a strong acid and completely dissociates in solution: \[ HCl \rightarrow H^+ + Cl^- \] - The concentration of \( H^+ \) from HCl is \( 1 \times 10^{-9} \) M. - However, we must also consider the contribution of \( H^+ \) from water, which is \( 1 \times 10^{-7} \) M at 298 K. - Total \( [H^+] = 1 \times 10^{-9} + 1 \times 10^{-7} \approx 1 \times 10^{-7} \) M. - Calculate pH: \[ \text{pH} = -\log(1 \times 10^{-7}) = 7 \] - Since pH = 7, this option is **not correct**. 3. **Option 2: \( 1 \times 10^{-5} \) M NaOH Solution**: - NaOH is a strong base and completely dissociates: \[ NaOH \rightarrow Na^+ + OH^- \] - The concentration of \( OH^- \) is \( 1 \times 10^{-5} \) M. - Calculate pOH: \[ \text{pOH} = -\log(1 \times 10^{-5}) = 5 \] - Calculate pH: \[ \text{pH} = 14 - \text{pOH} = 14 - 5 = 9 \] - Since pH = 9, this option is **correct**. 4. **Option 3: \( 1 \times 10^{-9} \) M KOH Solution**: - KOH is also a strong base and completely dissociates: \[ KOH \rightarrow K^+ + OH^- \] - The concentration of \( OH^- \) is \( 1 \times 10^{-9} \) M. - Calculate pOH: \[ \text{pOH} = -\log(1 \times 10^{-9}) = 9 \] - Calculate pH: \[ \text{pH} = 14 - \text{pOH} = 14 - 9 = 5 \] - Since pH = 5, this option is **not correct**. 5. **Option 4: (not provided)**: - Since we have already determined the outcomes of the first three options, we can conclude that the only solution with a pH of 9 is from Option 2. ### Conclusion: The solution that will have a pH of 9 at 298 K is the \( 1 \times 10^{-5} \) M NaOH solution.

To determine which of the following solutions will have a pH of 9 at 298 K, we need to analyze each option based on the relationship between pH, pOH, and the concentration of hydrogen ions (H⁺) and hydroxide ions (OH⁻) in the solution. ### Step-by-Step Solution: 1. **Understanding pH and pOH**: - pH is defined as \( \text{pH} = -\log[H^+] \) - pOH is defined as \( \text{pOH} = -\log[OH^-] \) - At 298 K, the relationship between pH and pOH is given by \( \text{pH} + \text{pOH} = 14 \). ...
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