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The pH values of 0.1 M solution of HCl, ...

The pH values of 0.1 M solution of HCl, CH3COOH, NH4Cl and CH3COONa will have the order :

A

`HCl lt CH_(3)COOH lt NH_(4)Cl lt CH_(3)COONa`

B

`CH_(3)COONa lt NH_(4)Cl lt CH_(3)COOH lt HCl`

C

`NH_(4)Cl lt CH_(3)COONa lt CH_(3)COOH lt HCl`

D

All will have same of pH value

Text Solution

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The correct Answer is:
To determine the order of pH values for a 0.1 M solution of HCl, CH3COOH, NH4Cl, and CH3COONa, we need to analyze each substance based on its properties as an acid, base, or salt. ### Step-by-Step Solution: 1. **Identify the nature of each compound:** - **HCl**: Strong acid that completely dissociates in solution. - **CH3COOH (Acetic Acid)**: Weak acid that partially dissociates in solution. - **NH4Cl (Ammonium Chloride)**: Salt of a weak base (NH3) and a strong acid (HCl), which will create an acidic solution upon hydrolysis. - **CH3COONa (Sodium Acetate)**: Salt of a weak acid (CH3COOH) and a strong base (NaOH), which will create a basic solution upon hydrolysis. 2. **Determine the pH of each solution:** - **HCl**: Since it is a strong acid, it completely dissociates, resulting in a high concentration of H⁺ ions. The pH is calculated as: \[ \text{pH} = -\log[H^+] = -\log[0.1] = 1 \] - **CH3COOH**: Being a weak acid, it does not fully dissociate. The pH will be higher than that of HCl. The dissociation can be represented as: \[ CH3COOH \rightleftharpoons H^+ + CH3COO^- \] The pH can be estimated using the dissociation constant (Ka), but it will be higher than 1. - **NH4Cl**: This salt will hydrolyze to produce NH4⁺ and Cl⁻. The NH4⁺ will react with water to produce H⁺ ions: \[ NH4^+ + H2O \rightleftharpoons NH3 + H^+ \] This results in an acidic solution, but the pH will be higher than that of HCl. - **CH3COONa**: This salt will hydrolyze to produce CH3COO⁻ and Na⁺. The CH3COO⁻ will react with water to produce OH⁻ ions: \[ CH3COO^- + H2O \rightleftharpoons CH3COOH + OH^- \] This results in a basic solution, leading to a pH greater than 7. 3. **Compare the pH values:** - HCl has the lowest pH (strongest acid). - NH4Cl has a higher pH than HCl but lower than CH3COOH (acidic solution). - CH3COOH has a higher pH than NH4Cl (weak acid). - CH3COONa has the highest pH (basic solution). 4. **Establish the order of pH values:** - The order of pH from lowest to highest is: \[ \text{HCl} < \text{NH4Cl} < \text{CH3COOH} < \text{CH3COONa} \] ### Final Answer: The order of pH values for the 0.1 M solutions is: \[ \text{HCl} < \text{NH4Cl} < \text{CH3COOH} < \text{CH3COONa} \]

To determine the order of pH values for a 0.1 M solution of HCl, CH3COOH, NH4Cl, and CH3COONa, we need to analyze each substance based on its properties as an acid, base, or salt. ### Step-by-Step Solution: 1. **Identify the nature of each compound:** - **HCl**: Strong acid that completely dissociates in solution. - **CH3COOH (Acetic Acid)**: Weak acid that partially dissociates in solution. - **NH4Cl (Ammonium Chloride)**: Salt of a weak base (NH3) and a strong acid (HCl), which will create an acidic solution upon hydrolysis. ...
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VMC MODULES ENGLISH-IONIC EQUILIBRIUM-LEVEL 2
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