A certain weak acid has a dissociation constant `10 xx 10^(-4)` . The equilibrium constant for its reaction with a strong base is `:`

Options

A. `1.0xx10^(-4)`
B. `1.0xx10^(-10)`
C. `1.0xx10^(10)`
D. `1.0xx10^(14)`

Answer

C

Explanation

The reaction of HA with strong base is
`HA + OH^(-) rarr H_(2)O + A^(-)`
`K = [A^(-)]/([HA][OH^(-)]) xx [H^(+)]/[H^(+)] = K_(a)/K_(w) = 10^(-4)/10^(-14) = 10^(10)`