Two liquids X and Y form an ideal solution. The mixture has a vapour pressure of 400 mm at 300 K when mixed in the molar ratio 1:1. when mixed in the molar ratio of 1:2 at the same temperatre the vapour pressure of the mixture is 350 mm. The vapour pressure of the two pure liquids X and Y respectively are

Options

A. 250 mm, 550 mm
B. 350 mm, 450 mm
C. 550 mm, 250 mm
D. 500 mm, 250 mm

Explanation

To solve the problem, we need to find the vapor pressures of the pure liquids X and Y based on the given information about their mixtures. We will use Raoult's law, which states that the vapor pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- When mixed in a 1:1 molar ratio, the vapor pressure of the mixture is 400 mm.
- When mixed in a 1:2 molar ratio, the vapor pressure of the mixture is 350 mm.

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