A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 300 mm at 300 K. The vapour pressure of pure propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol in the mixture is 0.375, then the vapour pressure (in mm) of pure ethyl alcohol at the same temperature will be :

Options

A. 466
B. 300
C. 700
D. 360

Explanation

To solve the problem step-by-step, we can follow these calculations:

### Step 1: Identify the given values
- Mole fraction of ethyl alcohol (XA) = 0.375
- Vapour pressure of pure propyl alcohol (P0B) = 200 mm
- Total vapour pressure of the mixture (P_total) = 300 mm

### Step 2: Calculate the mole fraction of propyl alcohol (XB)
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