Two solution of `H_(2)SO_(4)` of molarities x and y are mixed in the ratio of `V_(1) mL : V_(2) mL` to form a solution of molarity `M_(1)`. If they are mixed in the ratio of `V_(2) mL : V_(1) mL`, they form a solution of molarity `M_(2)`. Given `V_(1)//V_(2) = (x)/(y) gt 1 and (M_(1))/(M_(2)) = (5)/(4)`, then `x : y` is

Options

A. `2:1`
B. `4:1`
C. `1:2`
D. `3:1`

Explanation

To solve the problem, we need to analyze the mixing of two solutions of sulfuric acid (H₂SO₄) with molarities x and y. The solutions are mixed in two different volume ratios to yield two different molarities, M₁ and M₂.

### Step-by-Step Solution:

1. **Understanding the Problem:**
- We have two solutions with molarities x and y.
- They are mixed in the ratio V₁ : V₂ to form a solution of molarity M₁.
- When mixed in the ratio V₂ : V₁, they form a solution of molarity M₂.
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