A and B are ideal gases. The molecular weights of A and B are in the ratio of `1 : 4`. The pressure of a gas mixture containing equal weights of A and B is P atm. What is the partial pressure (in atm.) of B in the mixture

Options

A. `p/5`
B. `p/2`
C. `p/2.5`
D. `(3p)/4`

Explanation

To solve the problem, we need to determine the partial pressure of gas B in a mixture of two ideal gases A and B, given that their molecular weights are in the ratio of 1:4 and that equal weights of A and B are present in the mixture.

### Step-by-Step Solution:

1. **Define the Molecular Weights**:
- Let the molecular weight of gas A be \( m \).
- Since the ratio of the molecular weights of A and B is \( 1:4 \), the molecular weight of gas B will be \( 4m \).

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