When 25 g of a non-volatile solute is dissolved in 100 g of water, the vapour pressure is lowered by `2.25xx10^(-1)mm` of Hg. What is the molecular weight of the solute? [`P^(@)= 17.73` mm of Hg]

Options

A. 206
B. 302
C. 350
D. 276

Explanation

To find the molecular weight of the non-volatile solute, we can follow these steps:

### Step 1: Understand the Given Information
We are given:
- Mass of solute (m) = 25 g
- Mass of solvent (water) (M) = 100 g
- Lowering of vapor pressure (ΔP) = 2.25 × 10^(-1) mm of Hg = 0.225 mm of Hg
- Vapor pressure of pure solvent (P₀) = 17.73 mm of Hg
...