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A solution prepared by dissolving a 2.50...

A solution prepared by dissolving a 2.50 g sample of an unknown compound dissolved in `34.0` g on benzene , `C_(6)H_(6)` , boils `1.38^(@) C ` higher than pure benzene . Which expression gives the molar mass of the unknown compound ? Given that Kb of benzene = 2.53 unit

A

`2.53xx2.50/1.38`

B

`1.38xx34/2.53xx2.50`

C

`2.5xx2.53/34xx1/1.38`

D

`2.5xx1.38/34xx2.53`

Text Solution

Verified by Experts

`M_("solute")^(@)=(K_(B)xxW_("solute"(g))xx1000)/(W_("solvent"(g))xx(DeltaT_(B)))`
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