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1 mol benzene (P^(@)("benzene")=42 mm) ...

1 mol benzene `(P^(@)_("benzene")=42 mm)` and 2 mol toluence `(P^(@)_("toluene")=36 mm)` will have

A

total vapour pressure 38 mm

B

mol fraction of vapours of benzene above liquid mixture is 7/19

C

positive deviation from Raoult's law

D

negative deviation from Raoult's law

Text Solution

Verified by Experts

Benzene and Toluene Ideal solution
`P_("Total")=P_(A)^(@)chi_(A)=P_(B)^(@)chi_(B)=42xx1/3+36xx2/3=38` mm Hg.
`chi_("Benzene")^(v)=(P_("Benzene"))/(P_("Total"))=(42xx1/3)/38=7/19`
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