Home
Class 12
CHEMISTRY
The depression in freezing point of 0.01...

The depression in freezing point of `0.01 m` aqueous `CH_(3)CooH` solution is `0.02046^(@)`, `1 m` urea solution freezes at `-1.86^(@)C`. Assuming molality equal to molarity, `pH` of `CH_(3)COOH` solution is

Text Solution

Verified by Experts

`DeltaT_(f)=K_(f)mxxi`
`i=(0.02046)/(0.01xx1.86)=1.1=1+x`
`:.x=0.1`
`[H^(+)]=C alpha=0.01xx0.1=10^(-3)`
`pH=3`
Promotional Banner

Topper's Solved these Questions

  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|57 Videos
  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos
  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos
  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise EXERCISE-J|10 Videos
  • THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|31 Videos

Similar Questions

Explore conceptually related problems

The lowest freezing point of 0.1 M aqueous solution is of:

If the freezing point of 0.1 M HA(aq) solution is -0.2046^(@)C then pH of solution is ( If K_(f) water =1.86mol^(-1)kg^(-1))

Calculate the Delta T_f (depression in freezing point) of 0.4 m solution of CH_3 COOH in benzene solution. K_f = x K kg mol^-1 .

The freezing point of 0.05 m solution of glucose in water is (K1 = 1.86°C m^(-1) )

Why is freezing point depression of 0.1 M sodium chloride solution nearly twice that of 0.1 M glucose solution ?

The freezing point of of aqueous solution that contains 3% urea. 7.45% KCl and 9% of glucose is (given K_(f) of water =1.86 and asume molarity = molality)

Calculate the freezing point depression expected for 0.0711 m aqueous solution of Na_(2)SO_(4) . If this solution actually freezes at -0.320 ^(@)C , what would be the value of Van't Hoff factor ? ( K_(f) for water is 1.86 ^(@)C mol^(-1) ) .

0.1 M CH_(3)COOH solution is titrated against 0.05 M NaOH solution. Calculate pH at 1//4 ^(th) and stages of neutrazation of acid.The pH for 0.1 M CH_3COOH is 3.

The cryoscopic constant of water is 1.86 K "mol"^(-1) kg. An aqueous solution of cane sugar freezes at -0.372^(@)C . Calculate the molality of the solution.

In coparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_(2) solution is……

VMC MODULES ENGLISH-THEORY OF SOLUTIONS-LEVEL 2
  1. Two equimolar solutions have osmotic pressures in the ratio of 2 : 1 a...

    Text Solution

    |

  2. Human blood gives rise to an osmotic pressure of approximately 7.65 at...

    Text Solution

    |

  3. Osmotic pressure of insulin solution at 298 K is found to be 0.0072atm...

    Text Solution

    |

  4. Out of the compounds below, the vapour pressure of (B) at a particular...

    Text Solution

    |

  5. How much urea must be dissolved in 10^(-2)m^(3) water to yield a press...

    Text Solution

    |

  6. Acetic acid exists in benzene solution in the dimeric form. In an actu...

    Text Solution

    |

  7. Calculate the mass of a non-volatile solute (molar mass 40 g mol^(-1))...

    Text Solution

    |

  8. 1000gm of sucrose solution in water is cooled to -0.5^(@)C. How much ...

    Text Solution

    |

  9. The depression in freezing point of 0.01 m aqueous CH(3)CooH solution ...

    Text Solution

    |

  10. When 20 g of naphthoic acid (C(11)H(8)O(2)) is dissolved in 50 g of be...

    Text Solution

    |

  11. 75.2 g of phenol is dissolved in a solvent of Kf=14. If the depression...

    Text Solution

    |

  12. A storage battery contains a solution of H(2)SO(4) 38% by weight. At t...

    Text Solution

    |

  13. Calculate the apparent degree of ionisation of an electrolyte MX(2) i...

    Text Solution

    |

  14. The vapour pressure of a solution of a non-volatile electrolyte B in a...

    Text Solution

    |

  15. The relative lowering of the vapour pressure of an aqueous solution co...

    Text Solution

    |

  16. A 5 per cent aqueous solution by mass of a non-volatile solute boils a...

    Text Solution

    |

  17. One gram of serum albumin dissolved in 1000cm^(3) of water gives a sol...

    Text Solution

    |

  18. Density of a 2.05 M solution of acetic acid in water is 1.02 g/mL. The...

    Text Solution

    |

  19. The freezing point of 0.08 molal NaHSO(4) is -0.345^(@)C. Calculate th...

    Text Solution

    |

  20. Freezing point of 0.2 M KCN solution is -0.7^(@)C. On adding 0.1 mole ...

    Text Solution

    |