A 5 per cent aqueous solution by mass of a non-volatile solute boils at `100.15^(@)C`. Calculate the molar mass of the solute. `K_(b)=0.52 K kg "mol"^(-1)`.

Explanation

To find the molar mass of the non-volatile solute in a 5% aqueous solution that boils at 100.15°C, we can follow these steps:

### Step 1: Determine the change in boiling point (ΔTb)
The normal boiling point of water (Tb0) is 100°C. The boiling point of the solution (Tb) is given as 100.15°C.

\[ \Delta T_b = T_b - T_{b0} = 100.15°C - 100°C = 0.15°C \]
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