The density (in `g m L^(-1)`) of a 3.60 M sulphuric acid solution that is 29% `H_(2)SO_(4)` by mass will be:

Options

A. 1.64
B. 1.88
C. 1.22
D. 1.45

Explanation

Let the density fo solution be d
Molarity of solution given `=3.6m`
i.e. 1 litre of solution contains 3.6 moles of `H_(2)SO_(4)`
or 1 litre of solution contains `3.6xx98` m of `H_(2)SO_(4)`
since, the solution of 29% by mass.
100 gm solution contains 29 m `H_(2)SO_(4)`.
`100/d` ml solution contains 29 gm of `H_(2)SO_(4)`.
1000 ml solution contains `3.6xx98` gm of `H_(2)SO_(4)`
`:.3.6xx98=(29xxd)/100 xx 1000impliesd=1.22`