A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300K. The vapour pressure of propyl alcohol is 200 mm. if the mole fraction of ethyl alcohol is `0.6`, its vapour pressure (in mm) at the same temperature will be

Options

A. 350
B. 300
C. 700
D. 360

Explanation

To solve the problem, we will use Raoult's Law, which states that the total vapor pressure of a solution is equal to the sum of the partial vapor pressures of each component. The partial vapor pressure of each component can be calculated using the formula:

\[ P_{\text{total}} = P_{A} \cdot X_{A} + P_{B} \cdot X_{B} \]

Where:
- \( P_{\text{total}} \) is the total vapor pressure of the mixture.
- \( P_{A} \) is the vapor pressure of component A (propyl alcohol in this case).
- \( P_{B} \) is the vapor pressure of component B (ethyl alcohol in this case).
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