The vapour pressure of water at `20^(@)` C is 17.5 mm Hg. If 18 g of gulucose`(C_(6)H_(12)O_(6))` is added to 178.2 g of water at `20^(@)` C, the vapour pressure of the resulting solution will be:

Options

A. 17.675 mm Hg
B. 15.750 mm Hg
C. 16.500 mm Hg
D. 17.325 mm Hg

Explanation

To find the vapor pressure of the resulting solution when 18 g of glucose is added to 178.2 g of water at 20°C, we can use Raoult's Law. Here’s how to solve the problem step by step:

### Step 1: Calculate the number of moles of glucose (C₆H₁₂O₆)
The molar mass of glucose is calculated as follows:
- Carbon (C): 12 g/mol × 6 = 72 g/mol
- Hydrogen (H): 1 g/mol × 12 = 12 g/mol
- Oxygen (O): 16 g/mol × 6 = 96 g/mol

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