On mixing, heptane and octane form an ideal solution. At `373K` the vapour pressure of the two liquid components (heptane and octane) are `105 kPa` and `45 kPa` respectively. Vapour pressure of the solution obtained by mixing `25.0` of heptane and `35g` of octane will be (molar mass of heptane `= 100 g mol^(-1)` and of octane `= 114 g mol^(-1))`:-

Options

A. 72.0 kPa
B. 36.1 kPa
C. 96.2 kPa
D. 144.5 kPa

Explanation

To find the vapor pressure of the solution obtained by mixing heptane and octane, we will follow these steps:

### Step 1: Gather the given data
- Mass of heptane (m₁) = 25.0 g
- Mass of octane (m₂) = 35.0 g
- Molar mass of heptane (M₁) = 100 g/mol
- Molar mass of octane (M₂) = 114 g/mol
- Vapor pressure of pure heptane (P₀A) = 105 kPa
...