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The degree of dissociation (alpha) of a...

The degree of dissociation `(alpha)` of a weak electrolyte `A_(x)B_(y)` is related to van't Hoff factor (i) by the expression

A

`alpha=(i-1)/(x+y-1)`

B

`alpha=(i-1)/((x+y+1))`

C

`alpha=((x+y-1))/(i-1)`

D

`alpha=((x+y+1))/(i-1)`

Text Solution

AI Generated Solution

To derive the relationship between the degree of dissociation (α) of a weak electrolyte \( A_xB_y \) and the van't Hoff factor (i), we can follow these steps: ### Step 1: Understanding Weak Electrolytes A weak electrolyte is a substance that does not completely dissociate into ions in solution. Only a fraction of it dissociates. ### Step 2: Writing the Dissociation Reaction For a weak electrolyte \( A_xB_y \), the dissociation can be represented as: \[ ...
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