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Determination of the molar mass of aceti...

Determination of the molar mass of acetic acid in benzene using freezing point depression is affected by :

A

dissociation

B

association

C

partial ionization

D

complex formation

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AI Generated Solution

To determine the molar mass of acetic acid in benzene using freezing point depression, we need to understand how certain factors affect this measurement. Here’s a step-by-step solution: ### Step 1: Understand Freezing Point Depression Freezing point depression is a colligative property, which means it depends on the number of solute particles in a solution rather than the identity of the solute. The formula for freezing point depression is given by: \[ \Delta T_f = i \cdot K_f \cdot m \] ...
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The solution of acetic acid in benzene contains

Each question contains STATEMENT-I(Assertion) and STATEMENT-2(Reason).the statement carefully and mark the correct answer according to the instruction given below: STATEMENT - 1 : The molecular mass of acetic acid determined by depression in freezing point method in benzene and water was found to be differrent. STATEMENT - 2 : Water is polar and benzene is non-polar.

Statement-1 : The observed molar mass of acetic acid in benzene is more than the normal molar mass of acetic acid. Statement-2 : Molecules of acetic and dimerise in benzene due to hydrogen bonding.

Read the paragraph carefully and answer the following questions: Mole fraction of acetic acid in benzene given a solution having freezing point 277.4K. Freezing point of benezene is 278.4K and heat of fusion of benzene is 10.042 kJ/mol. If molarity of solution is equal to molality, and acetic acid is found in equilibrium with it dimmer than answer the following based upon above data The degree of association according to above data acetic acid should be

Read the paragraph carefully and answer the following questions: Mole fraction of acetic acid in benzene given a solution having freezing point 277.4K. Freezing point of benezene is 278.4K and heat of fusion of benzene is 10.042 kJ/mol. If molarity of solution is equal to molality, and acetic acid is found in equilibrium with it dimmer than answer the following based upon above data Calculate the equilibrium constant for dimerisation of acetic acid

Calculate the molar mass of sodium acetate.

From a measurement of the freezing point depression of benzene, the molecular weight of acetic acid in a benzene solution was determined to be 100 . The percentage association of acetic acid is

Consider the following statements and arrange in order of true/false as given in the codes. S_1 : Vapour pressure is a colligative property. S_2 :Freezing point of a solution is always lower than of the pure solvent S_3 : Acetic acid undergoes association in benzene The molar mass of acetic acid, determined by elevation of boiling point is always higher than its normal molar mass. S_4 : Osomotic pressure measurements can be used for determination of molar mass of polymers.

Derive a formula determining molecular mass from depression in freezing point.

1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

VMC MODULES ENGLISH-THEORY OF SOLUTIONS-JEE Main (Archive)
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  2. A solution at 20^(@)C is composed of 1.5 mol of benzene and 3.5 mol o...

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  3. Determination of the molar mass of acetic acid in benzene using freezi...

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  4. 18 g glucose (C(6)H(12)O(6)) is added to 178.2 g water. The vapour pre...

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  7. The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of ace...

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  11. For 1 molal aqueous solution of the following compounds, which one wil...

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  13. The mass of a non-volatile, non-electrolyte solute ("molar mass" = 50 ...

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  16. Elevation in the boiling point for 1 molal solution of glucose is 2K. ...

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  17. The freezing point of a diluted milk sample is found to be-0.2^(@)C, w...

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  18. Freezing point of a 4% aqueous solution of X is equal to freezing ...

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