At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea `=60 g "mol"^(-1)`)

Options

A. 0.027 mm Hg
B. 0.031 mm Hg
C. 0.017 mm Hg
D. 0.28 mm Hg

Explanation

To find the lowering of vapor pressure when 0.60 g of urea is dissolved in 360 g of water, we can follow these steps:

### Step 1: Calculate the number of moles of urea.
Given:
- Mass of urea = 0.60 g
- Molar mass of urea = 60 g/mol

Using the formula for moles:
...