A solution is prepared by dissolving 0.6 g of urea (molar mass `=60 g"mol"^(-1)`) and 1.8 g of glucose (molar mass `=180g"mol"^(-1)`) in 100 mL of water at `27^(@)C`. The osmotic pressure of the solution is:
`(R=0.8206L "atm"K^(-1)"mol"^(-1))`

Options

A. 1.64 atm
B. 4.92 atm
C. 8.2 atm
D. 2.46 atm

Explanation

To find the osmotic pressure of the solution prepared by dissolving urea and glucose, we can follow these steps:

### Step 1: Identify the given data
- Mass of urea = 0.6 g
- Molar mass of urea = 60 g/mol
- Mass of glucose = 1.8 g
- Molar mass of glucose = 180 g/mol
- Volume of solution = 100 mL = 0.1 L
...