0.2 molal acid HX is 20% ionised in solution, `K_(f)=1.86K "molality"^(-1)`. The freezig point of the solution is

Options

A. `-0.45`
B. `-0.90`
C. `-0.31`
D. `-0.53`

Explanation

To find the freezing point of a 0.2 molal solution of acid HX that is 20% ionized, we will follow these steps:

### Step 1: Determine the degree of ionization (α)
Given that the acid HX is 20% ionized, we can express this as:
\[ \alpha = \frac{20}{100} = 0.2 \]

...